Physics · Scalars and Vectors
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The Sum of 2 forces acting at a point is 16N. If the resultant force is 8N and its direction is perpendicular to minimum force, then the force is:
- A
6N and 10N
- B
8N and 8N
- C
4N and 12N
- D
None of them
Correct option is A)
A+B=16...(1)
Tanα = Bsinθ/A+Bcosθ = tan90
Thus, A+Bcosθ = 0 ⇒cosθ = − A/B ...(2)
We also have:
8= √A^2 +B^2 +2ABcosθ ...(3)
Solving these we get, A=6N and B=10N
As it is numerical, it can have only one possible answer.
Correct option is A)
A+B=16...(1)
Tanα = Bsinθ/A+Bcosθ = tan90
Thus, A+Bcosθ = 0 ⇒cosθ = − A/B ...(2)
We also have:
8= √A^2 +B^2 +2ABcosθ ...(3)
Solving these we get, A=6N and B=10N
As it is numerical, it can have only one possible answer.
this option is incorrect.
Correct option is A)
A+B=16...(1)
Tanα = Bsinθ/A+Bcosθ = tan90
Thus, A+Bcosθ = 0 ⇒cosθ = − A/B ...(2)
We also have:
8= √A^2 +B^2 +2ABcosθ ...(3)
Solving these we get, A=6N and B=10N
As it is numerical, it can have
this option is incorrect.
Correct option is A)
A+B=16...(1)
Tanα = Bsinθ/A+Bcosθ = tan90
Thus, A+Bcosθ = 0 ⇒cosθ = − A/B ...(2)
We also have:
8= √A^2 +B^2 +2ABcosθ ...(3)
Solving these we get, A=6N and B=10N
As it is numerical, it can have
this option is incorrect.
Correct option is A)
A+B=16...(1)
Tanα = Bsinθ/A+Bcosθ = tan90
Thus, A+Bcosθ = 0 ⇒cosθ = − A/B ...(2)
We also have:
8= √A^2 +B^2 +2ABcosθ ...(3)
Solving these we get, A=6N and
B=10N
As it is numerical, it can have
Tagged under Physics · Scalars and Vectors · 2017