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MDCAT
Physics
2014

Physics · Optics, Nature of Light and Optical Instruments

Work through this past-paper style MCQ, then read the full explanation. Practice more physics questions on mMCQ with adaptive practice and topic analytics.

Question

In a compound microscope, the magnification by objective = 20, magnification by eyepiece = 11, then the total magnification is

 

Options
  • A

    M = -220 

  • B

    M = -0.19 

  • C

    M = -0.05 

  • D

    M = 220 

Explanation

The explanation is given below:

To find the total magnification of two lenses combined we must multiply individual magnifications:

20x11 = -220

This option is incorrect as per the formula.M = M_{objective} \times M_{eyepiece}

Given:

M_{objective} = 20

M_{eyepiece} = 11

Therefore, the total magnification is:

M = 20 \times 11 = 220

This option is incorrect as per the formula.M = M_{objective} \times M_{eyepiece}

Given:

M_{objective} = 20

M_{eyepiece} = 11

Therefore, the total magnification is:

M = 20 \times 11 = 220

This option is incorrect as per the formula.M = M_{objective} \times M_{eyepiece}

Given:

M_{objective} = 20

M_{eyepiece} = 11

Therefore, the total magnification is:

M = 20 \times 11 = 220

This option is correct.

To find the total magnification of two lenses combined we must multiply individual magnifications:

20x11 = 220

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Tagged under Physics · Optics, Nature of Light and Optical Instruments · 2014