Physics · Forces and Motion

This is the correct answer. We can use the equation of motion: v^2 = u^2 + 2as, where v is the final velocity (0 m/s at the maximum height), u is the initial velocity (19.6 m/s), a is the acceleration due to gravity (-9.8 m/s^2), and s is the displacement (maximum height). Plugging in these values and solving for s gives us 19.6 m. 

This is the correct answer. We can use the equation of motion: v^2 = u^2 + 2as, where v is the final velocity (0 m/s at the maximum height), u is the initial velocity (19.6 m/s), a is the acceleration due to gravity (-9.8 m/s^2), and s is the displacement (maximum height). Plugging in these values and solving for s gives us 19.6 m. 

This answer is incorrect because it assumes that the acceleration due to gravity is constant throughout the entire motion, even when the handball is at its maximum height. In reality, the acceleration due to gravity decreases with distance from the Earth's surface.Therefore, the handball will not reach a height of 39.2 m. 

This answer is incorrect because it assumes that the handball reaches its maximum height after only one second of flight. However, the handball will continue to rise until its upward velocity is reduced to zero. This will take longer than one second.

This answer is incorrect because it assumes that the handball reaches its maximum height after only half a second of flight. This is not the case, as the handball will continue to rise until its upward velocity is reduced to zero.