Physics · Electrostatics
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What is the change in kinetic energy of a proton when it is accelerated through a potential difference of 2MV?
- A
0.32 μJ
- B
0.32 nJ
- C
0.32 pJ
- D
0.32 fJ
Change in Kinetic energy is equivalent to work done.
We know that W = Vq
Where W is the work done, V is the potential difference through which the charged particle is accelerated, and q is the magnitude of charge.
W = 2x106 (1.6x10-19)
= 3.2x10-13J
= 0.32 pJ
Incorrect as per formula
Incorrect as per formula
Change in Kinetic energy is equivalent to work done.
We know that W = Vq
Where W is the work done, V is the potential difference through which the charged particle is accelerated, and q is the magnitude of charge.
W = 2x106 (1.6x10-19)
= 3.2x10-13J
= 0.32 pJ
Incorrect as per formula
Tagged under Physics · Electrostatics