Physics · Current Electricity
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A light bulb draws 300 mA when the voltage across it is 240V. The resistance of the light bulb is:
- A
400 ohm
- B
600 ohm
- C
800 ohm
- D
1000 ohm
The measure of opposition applied by any object to the flow of electric current is known as resistance Resistance = Voltage / Current V= 240 V Current = 300 mA = 0.3 A R = 240/0.3 Resistance = 800 ohm Mathematically options A,B&D are incorrect
Incorrect as per the calculation.
Incorrect as per the calculation.
The measure of opposition applied by any object to the flow of electric current is known as resistance
Resistance = Voltage / Current
V= 240 V
Current = 300 mA = 0.3 A
R = 240/0.3
Resistance = 800 ohm
Mathematically options A, B & D are incorrect
Incorrect as per the calculation.
Tagged under Physics · Current Electricity · 2021