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MDCAT
Chemistry
2024

Chemistry · Hydrocarbons

Work through this past-paper style MCQ, then read the full explanation. Practice more chemistry questions on mMCQ with adaptive drills and topic analytics.

Question

Which one of the following represents nitration of benzene correctly?

Options
  • A


  • B


  • C


  • D


Explanation

Benzene reacts with concentrated nitric acid (HNO₃) in the presence of concentrated sulfuric acid (H₂SO₄) at 50–55°C. Sulfuric acid acts as a catalyst and generates the electrophile (NO₂⁺, nitronium ion), which attacks the benzene ring via electrophilic aromatic substitution, forming nitrobenzene and water as a by-product.

Benzene reacts with concentrated nitric acid (HNO₃) in the presence of concentrated sulfuric acid (H₂SO₄) at 50–55°C. Sulfuric acid acts as a catalyst and generates the electrophile (NO₂⁺, nitronium ion), which attacks the benzene ring via electrophilic aromatic substitution, forming nitrobenzene and water as a by-product.

Benzene reacts with concentrated nitric acid (HNO₃) in the presence of concentrated sulfuric acid (H₂SO₄) at 50–55°C. Sulfuric acid acts as a catalyst and generates the electrophile (NO₂⁺, nitronium ion), which attacks the benzene ring via electrophilic aromatic substitution, forming nitrobenzene and water as a by-product.

Benzene reacts with concentrated nitric acid (HNO₃) in the presence of concentrated sulfuric acid (H₂SO₄) at 50–55°C. Sulfuric acid acts as a catalyst and generates the electrophile (NO₂⁺, nitronium ion), which attacks the benzene ring via electrophilic aromatic substitution, forming nitrobenzene and water as a by-product.

Benzene reacts with concentrated nitric acid (HNO₃) in the presence of concentrated sulfuric acid (H₂SO₄) at 50–55°C. Sulfuric acid acts as a catalyst and generates the electrophile (NO₂⁺, nitronium ion), which attacks the benzene ring via electrophilic aromatic substitution, forming nitrobenzene and water as a by-product.

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Tagged under Chemistry · Hydrocarbons · 2024