Physics · Scalars and Vectors
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If A = 2i+j+2k then its magnitude is:
- A
9
- B
5
- C
3
- D
1
To calculate the magnitude of a vector, we can use the formula:
|A| = √(Ax² + Ay² + Az²
Where 'A' is the vector and Ax, Ay, and Az are the components of the vector in the x, y, and z directions, respectively.
We have,
-A = 2i + j + 2k
Let's calculate the magnitude:
|-A| = √(2)² + (1)² + (2)²
= √ (4+1+4)
= √(9)
= 3
Therefore, the magnitude of the vector -A is 3.
To calculate the magnitude of a vector, we can use the formula:
|A| = √(Ax² + Ay² + Az²
Where 'A' is the vector and Ax, Ay, and Az are the components of the vector in the x, y, and z directions, respectively.
We have,
-A = 2i + j + 2k
Let's calculate the magnitude:
|-A| = √(2)² + (1)² + (2)²
= √ (4+1+4)
= √(9)
= 3
Therefore, the magnitude of the vector -A is 3.
To calculate the magnitude of a vector, we can use the formula:
|A| = √(Ax² + Ay² + Az²
Where 'A' is the vector and Ax, Ay, and Az are the components of the vector in the x, y, and z directions, respectively.
We have,
-A = 2i + j + 2k
Let's calculate the magnitude:
|-A| = √(2)² + (1)² + (2)²
= √ (4+1+4)
= √(9)
= 3
Therefore, the magnitude of the vector -A is 3.
To calculate the magnitude of a vector, we can use the formula:
|A| = √(Ax² + Ay² + Az²
Where 'A' is the vector and Ax, Ay, and Az are the components of the vector in the x, y, and z directions, respectively.
We have,
-A = 2i + j + 2k
Let's calculate the magnitude:
|-A| = √(2)² + (1)² + (2)²
= √ (4+1+4)
= √(9)
= 3
Therefore, the magnitude of the vector -A is 3.
To calculate the magnitude of a vector, we can use the formula:
|A| = √(Ax² + Ay² + Az²
Where 'A' is the vector and Ax, Ay, and Az are the components of the vector in the x, y, and z directions, respectively.
We have,
-A = 2i + j + 2k
Let's calculate the magnitude:
|-A| = √(2)² + (1)² + (2)²
= √ (4+1+4)
= √(9)
= 3
Therefore, the magnitude ofp the vector -A is 3.
Tagged under Physics · Scalars and Vectors · 2010