Physics · States of Matter - Gases, Liquids and Solids
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Pressure exerted by perfect gas is equal to :
- A
⅓ mean K.E/volume
- B
½ Mean K.E/volume
- C
⅔ mean K.E/volume
- D
Mean K.E/volume
2/3 mean K.E/volume: This option is correct. The pressure exerted by an ideal gas is numerically equal to two-third of the mean kinetic energy of translation per unit volume of the gas. Hence, pressure is two-third of mean KE per unit volume.
1/3 mean K.E/volume: This option is incorrect. The pressure of a perfect gas is not directly related to one-third of the mean kinetic energy divided by volume.
1/2 mean K.E/volume: This option is incorrect. The pressure of a perfect gas is not directly related to one-half of the mean kinetic energy divided by volume.
2/3 mean K.E/volume: This option is correct. The pressure exerted by an ideal gas is numerically equal to two-third of the mean kinetic energy of translation per unit volume of the gas. Hence, pressure is two-third of mean KE per unit volume.
Mean K.E/volume: This option is incorrect. The pressure of a perfect gas is not directly related to the mean kinetic energy divided by volume.
Tagged under Physics · States of Matter - Gases, Liquids and Solids · 2009