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MDCAT
Biology
2006

Biology · Variation and Genetics

Work through this past-paper style MCQ, then read the full explanation. Practice more biology questions on mMCQ with adaptive practice and topic analytics.

Question

On the basis of which of the following ratio we can prove law of independence assortment? 

Options
  • A

    9:3:3:1

  • B

    9:3:4

  • C

    1:2:1

  • D

    2:11

Explanation

The correct ratio for demonstrating the law of independent assortment is 9:3:3:1. This ratio results from a dihybrid cross where two heterozygous parents are crossed, and each trait is inherited independently according to Mendel's second law. This ratio is obtained by considering the combination of two pairs of alleles, each pair segregating independently during gamete formation. The other ratios provided do not demonstrate independent assortment: 9:3:4 is related to epistasis, 1:2:1 is typical of incomplete dominance in a monohybrid cross, and 2:11 does not represent a standard genetic ratio.

This is the classic phenotypic ratio observed in a dihybrid cross involving two pairs of independently assorting alleles. It reflects the law of independent assortment.

This ratio is typically associated with epistasis, where one gene affects the expression of another, and not with independent assortment.

This ratio is commonly associated with a monohybrid cross involving incomplete dominance, not a dihybrid cross.

This ratio does not correspond to any standard genetic cross and is not applicable to the law of independent assortment.

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Tagged under Biology · Variation and Genetics · 2006