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MDCAT
Physics
2009

Physics · Optics, Nature of Light and Optical Instruments

Work through this past-paper style MCQ, then read the full explanation. Practice more physics questions on mMCQ with adaptive practice and topic analytics.

Question

An object Is placed 60 cm in front of a concave spherical mirror whose focal lenght is 40cm. which of the folowing best described the image?

MDCAT Physics question — Optics, Nature of Light and Optical Instruments
Options
  • A

    Option A

  • B

    Option B

  • C

    Option C

  • D

    Option D

  • E

    Option E

Explanation

Substituting values into the formula
1/f= 1/v - 1/u
1/-40= 1/v - 1/60
1/v= 1/60 - 1/40
1/v= -1/120
v= -120 cm
Since the object is placed between f and 2f, the image formed will be real (refer to the table) and 120 cm from the mirror. Therefore option D is correct.

This option is incorrect.Substituting values into the formula

1/f= 1/v - 1/u

1/-40= 1/v - 1/60

1/v= 1/60 - 1/40

1/v= -1/120

v= -120 cm

Since the object is placed between f and 2f, the image formed will be real (refer to the table) and 120 cm from the mirror. Therefore option D is correct.

This option is incorrect. Substituting values into the formula

1/f= 1/v - 1/u

1/-40= 1/v - 1/60

1/v= 1/60 - 1/40

1/v= -1/120

v= -120 cm

Since the object is placed between f and 2f, the image formed will be real (refer to the table) and 120 cm from the mirror. Therefore option D is correct.

This option is incorrect. Substituting values into the formula

1/f= 1/v - 1/u

1/-40= 1/v - 1/60

1/v= 1/60 - 1/40

1/v= -1/120

v= -120 cm

Since the object is placed between f and 2f, the image formed will be real (refer to the table) and 120 cm from the mirror. Therefore option D is correct.

Substituting values into the formula

1/f= 1/v - 1/u

1/-40= 1/v - 1/60

1/v= 1/60 - 1/40

1/v= -1/120

v= -120 cm

Since the object is placed between f and 2f, the image formed will be real (refer to the table) and 120 cm from the mirror. Therefore option D is correct. 

This option is incorrect. Substituting values into the formula

1/f= 1/v - 1/u

1/-40= 1/v - 1/60

1/v= 1/60 - 1/40

1/v= -1/120

v= -120 cm

Since the object is placed between f and 2f, the image formed will be real (refer to the table) and 120 cm from the mirror. Therefore option D is correct.

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Tagged under Physics · Optics, Nature of Light and Optical Instruments · 2009