Physics · Oscillations and Simple Harmonic Motion
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The displacement 'x‘ of a particle at time 't‘ is given by x = 10 sin 4t. the particle oscillates with period.
- A
π/10s
- B
π/5s
- C
π/4s
- D
π/2s
x=10sin4t , period T=?
We know that
x=x°sinθ
x= x°sin wt
x=x° sin2πft
Comparing
10sin4t= x° sin2πft
4=2πf
4=2π/T
T=2π/4
T=π/2 sec ans
This period is incorrect. The angular frequency must match the standard form to find the correct period.
This period is incorrect. The formula used to find the period is not applied correctly here.
This period is incorrect. The angular frequency extracted from the equation leads to a different result.
This is the correct period. The equation x = 10 sin 4t indicates an angular frequency of 4 rad/s, resulting in a period of π/2 seconds.
Tagged under Physics · Oscillations and Simple Harmonic Motion · 2014