Chemistry · Electrochemistry
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In acidic medium, oxidation action of potassium permanganate depends upon:
- A
Mn7+
- B
KMnO2+
- C
MnO2
- D
Mn1+
- E
Mn4+
Equation for reduction of KMnO4 in acidic medium:
8H+ + MnO4- + 5e- ----> Mn2+ + 4H2O
Here in MnO4- the oxidation state of Mn is +7, and it is being reduced to Mn2+
Therefore, it acts as an oxidising agent as Mn7+ can gain elections from the substance being oxidised and get reduced itself.
In acidic medium the reaction for potassium permanganate can be given as:
8H+ + MnO4- + 5e- —> Mn2+ + 4H2O
From the equation it can be seen that the oxidation state of Mn is decreased from +7 to +2 so it acts as an oxidizing agent and resultantly the oxidation state of potassium permanganate depends on Mn+7.
In acidic medium the reaction for potassium permanganate can be given as
8H+ + MnO4- + 5e- —> Mn2+ + 4H2O
From the equation it can be seen that the oxidation state of Mn is decreased from +7 to +2 so it acts as an oxidizing agent and resultantly the oxidation state of potassium permanganate depends on Mn+7.
In acidic medium the reaction for potassium permanganate can be given as
8H+ + MnO4- + 5e- —> Mn2+ + 4H2O
From the equation it can be seen that the oxidation state of Mn is decreased from +7 to +2 so it acts as an oxidizing agent and resultantly the oxidation state of potassium permanganate depends on Mn+7.
In acidic medium the reaction for potassium permanganate can be given as
8H+ + MnO4- + 5e- —> Mn2+ + 4H2O
From the equation it can be seen that the oxidation state of Mn is decreased from +7 to +2 so it acts as an oxidizing agent and resultantly the oxidation state of potassium permanganate depends on Mn+7.
False.
Tagged under Chemistry · Electrochemistry · 2018