Physics · Electrostatics
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Two capacitors C1 (12 F) and C2 (24 F) are connected in series across a 36 V supply. The charge stored on each of them will be:
- A
288 C, 288 C
- B
4770 C, 4770 C
- C
5810 C, 6610 C
- D
7170 C, 8140 C
In series, charge remains same. This cancels option C and D.
To calculate Total capacitance:
1/C = 1/12 + 1/24
C=8F
C=Q/V
8 x 36= 288C
Option A is therefore the correct answer.
We know when capacitors are in series ,charge through them is same
So C and D options are obviously wrong
As voltage given is equivalent Voltage
So we have to find equivalent capacitance to find charge
1/Ceq = 1/C1+ 1/ C2
1/Ceq = 1/ 12 + 1/ 24
1/Ceq = 1+2 / 24
Ceq = 24 / 3
= 8 F
Now ,
Q= CV
Q=8×36
Q=288C
So A option is right.
This option is incorrect based on calculations.
This is wrong because charge on both capacitors must be same when they are connected in series.
This is wrong because charge on both capacitors must be same when they are connected in series.
Tagged under Physics · Electrostatics · 2018