Chemistry · Alcohols, Phenols and Ether
Work through this past-paper style MCQ, then read the full explanation. Practice more chemistry questions on mMCQ with adaptive drills and topic analytics.
Sodium phenoxide on treating with hydrochloric acids yields:
- A
Benzene
- B
Benzoic acid
- C
Phenol
- D
Benzaldehyde
Here’s the following equation.
C6H5ONa + HCl → C6H5OH + NaCl
In this reaction, sodium phenoxide (C6H5ONa) reacts with hydrochloric acid (HCl) to yield phenol (C6H5OH) and sodium chloride (NaCl). The sodium phenoxide is protonated by the hydrochloric acid, resulting in the formation of phenol and sodium chloride as the salt byproduct.
Reaction mechanism is given below.
Reaction mechanism is given below.
C6H5ONa + HCl → C6H5OH + NaCl
In this reaction, sodium phenoxide (C6H5ONa) reacts with hydrochloric acid (HCl) to yield phenol (C6H5OH) and sodium chloride (NaCl). The sodium phenoxide is protonated by the hydrochloric acid, resulting in the formation of phenol and sodium chloride as the salt byproduct.
Reaction mechanism is given below.
Tagged under Chemistry · Alcohols, Phenols and Ether · 2017