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MDCAT
Chemistry
2017

Chemistry · Alcohols, Phenols and Ether

Work through this past-paper style MCQ, then read the full explanation. Practice more chemistry questions on mMCQ with adaptive practice and topic analytics.

Question

Sodium phenoxide on treating with hydrochloric acids yields:

Options
  • A

    Benzene

  • B

    Benzoic acid

  • C

    Phenol

  • D

    Benzaldehyde

Explanation

Here’s the following equation. 

C6H5ONa + HCl → C6H5OH + NaCl

In this reaction, sodium phenoxide (C6H5ONa) reacts with hydrochloric acid (HCl) to yield phenol (C6H5OH) and sodium chloride (NaCl). The sodium phenoxide is protonated by the hydrochloric acid, resulting in the formation of phenol and sodium chloride as the salt byproduct. 

Reaction mechanism is given below. 

Reaction mechanism is given below. 

C6H5ONa + HCl → C6H5OH + NaCl 

In this reaction, sodium phenoxide (C6H5ONa) reacts with hydrochloric acid (HCl) to yield phenol (C6H5OH) and sodium chloride (NaCl). The sodium phenoxide is protonated by the hydrochloric acid, resulting in the formation of phenol and sodium chloride as the salt byproduct.

Reaction mechanism is given below. 

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Tagged under Chemistry · Alcohols, Phenols and Ether · 2017