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MDCAT
Physics
2017

Physics · Alternating Current

Work through this past-paper style MCQ, then read the full explanation. Practice more physics questions on mMCQ with adaptive practice and topic analytics.

Question

The relation between an alternative current voltage source and time in international system units is:

V = 120 sin (100𝜋t) cos (100𝜋t) volt value of peak velocity and frequency will be respectively:-

Options
  • A

    120 volt and 100 Hz

  • B

    120/√2 volt and 100 Hz

  • C

    60 volt and 200 Hz

  • D

    60 volt and 100 Hz

Explanation

Explanation is given below.

This option is incorrect.

V=120sin(100πt)cos(100πt)V

We know: sin2𝜭=2sin𝜭cos𝜭

V= 60sin2(100πt)V

=60sin200πtV

Let's compare it with standard equation:

V=V0sinωt

Hence peak velocity V0 is= 60V.

ω=200π

We know frequency f=ω/2π

=200π/2π

=100Hz ans

This option is incorrect.

V=120sin(100πt)cos(100πt)V

We know: sin2𝜭=2sin𝜭cos𝜭

V= 60sin2(100πt)V

=60sin200πtV

Let's compare it with standard equation:

V=V0sinωt

Hence peak velocity V0 is= 60V.

ω=200π

We know frequency f=ω/2π

=200π/2π

=100Hz ans

This option is incorrect.

V=120sin(100πt)cos(100πt)V

We know: sin2𝜭=2sin𝜭cos𝜭

V= 60sin2(100πt)V

=60sin200πtV

Let's compare it with standard equation:

V=V0sinωt

Hence peak velocity V0 is= 60V.

ω=200π

We know frequency f=ω/2π

=200π/2π

=100Hz ans

V=120sin(100πt)cos(100πt)V

We know: sin2𝜭=2sin𝜭cos𝜭

V= 60sin2(100πt)V

  =60sin200πtV

Let's compare it with standard equation:

V=V0sinωt

Hence peak velocity V0 is= 60V. ans

ω=200π

We know frequency f=ω/2π                         

                                  =200π/2π

                                  =100Hz ans

The answer C in the key is incorrect, it should be D

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Tagged under Physics · Alternating Current · 2017