Physics · Physics of Solids
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A wire of length 2m is attached with mass of 5kg vertically, tensile strain of wire is 0.3x10-3, the extension in wire is:
- A
1.5mm
- B
2mm
- C
0.15mm
- D
0.6mm
Strain is nothing but ratio of change in length to original length i.e Δl/L. We are asked to calculate extension meaning increase in length i.e Δl.
strain= Δl/L
Δl =strain x L
=0.3x10-³ x 2
=0.6x10-³
=0.6mm ANS
This option is incorrect.
Strain is nothing but ratio of change in length to original length i.e Δl/L. We are asked to calculate extension meaning increase in length i.e Δl.
strain= Δl/L
Δl =strain x L
=0.3x10-³ x 2
=0.6x10-³
=0.6mm ANS
This option is incorrect.
Strain is nothing but ratio of change in length to original length i.e Δl/L. We are asked to calculate extension meaning increase in length i.e Δl.
strain= Δl/L
Δl =strain x L
=0.3x10-³ x 2
=0.6x10-³
=0.6mm ANS
This option is incorrect.
Strain is nothing but ratio of change in length to original length i.e Δl/L. We are asked to calculate extension meaning increase in length i.e Δl.
strain= Δl/L
Δl =strain x L
=0.3x10-³ x 2
=0.6x10-³
=0.6mm ANS
Strain is nothing but ratio of change in length to original length i.e Δl/L. We are asked to calculate extension meaning increase in length i.e Δl.
strain= Δl/L
Δl =strain x L
=0.3x10-³ x 2
=0.6x10-³
=0.6mm ANS
strain= Δl/L
Δl =strain x L
=0.3x10^-3 x 2
Strain is nothing but ratio of change in length to original length i.e Δl/L. We are asked to calculate extension meaning increase in length i.e Δl.
strain= Δl/L
Δl =strain x L
=0.3x10-³ x 2
=0.6x10-³
=0.6mm ANSstrain is nothing but ratio of change
Tagged under Physics · Physics of Solids · 2017