mMCQ.

Navigation Menu

Step into mMCQ.

Launch mMCQ. diagnostic

Explore mMCQ.

MDCAT prepFree DiagnosticPricing & SubscribeSign in

Resources

Terms & Conditions

mMCQ.

© 2021 - 2025 mMCQ.All rights reserved.

WhatsApp
  1. Home
  2. MDCAT
  3. Physics
  4. Magnetism and Electromagnetic Induction
MDCAT
Physics
2009

Physics · Magnetism and Electromagnetic Induction

Work through this past-paper style MCQ, then read the full explanation. Practice more physics questions on mMCQ with adaptive practice and topic analytics.

Question

What shunt resistance must be connected across a Galvanometer of 20 Ω resistance which gives full scale deflection with 2.0 A current, so as to convert it into an Ammeter of range 10 A?

Options
  • A

    5 Ω

  • B

    2 Ω

  • C

    3 Ω

  • D

    4 Ω

Explanation

Explanation: 

Galvanometer resistance = G = 20Ω

Current = I1 = 10A

Current = I2 = 2 A

Shunt resistance = Rs = ?

So,

n = I1 / I2

n = 10 / 2

= 5

Applying the formula:

Rs = G / n - 1

= 20 / 5 - 1

= 20 / 4

Rs = 5 ohms

This is the correct answer. The shunt resistance is calculated using the formula Rs = G / (n - 1), where n = I1 / I2. Substituting the given values, we find that Rs = 5 Ω.

This is incorrect. Using a shunt resistance of 2 Ω would not provide the desired ammeter range of 10 A. Double-check your calculations using the correct formula.

This is incorrect. A shunt resistance of 3 Ω is too low to achieve the required range conversion. Ensure you are using the correct formula and values.

This is incorrect. Using a shunt resistance of 4 Ω would not convert the galvanometer to the desired range of 10 A. Verify your calculations.

Keep practising Physics

Take the free 2 minutes diagnostic to map weak topics, then unlock full Biology, Chemistry, Physics, English, and Logical Reasoning practice for PKR 15,000/month.

Start free diagnosticExplore MDCAT

Tagged under Physics · Magnetism and Electromagnetic Induction · 2009