Physics · Work, Power & Energy
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A variable force F = x is applied what will be the work done in moving the particle from X= 0 to 1
- A
2 J
- B
1 J
- C
0.5 J
- D
5 J
The work done in moving a particle from x=0 to x=1 when a variable force F=x is applied can be found by integrating the force over the distance. The work done W is given by:
W = ∫x=0 to x=1 F(x) dx
W = ∫x=0 to x=1 x dx
W =[x2/2] from 0 to 1
W = (12/2) - (02/2)
W = 1/2 units of work
Therefore, the work done in moving the particle from x=0 to x=1 with a variable force F=x is 1/2 units of work.
Mathematically the options are incorrect.
The work done in moving a particle from x=0 to x=1 when a variable force F=x is applied can be found by integrating the force over the distance. The work done W is given by:
W = ∫x=0 to x=1 F(x) dx
W = ∫x=0 to x=1 x dx
W =[x2/2] from 0 to 1
W = (12/2) - (02/2)
W = 1/2 units of work
The work done in moving a particle from x=0 to x=1 when a variable force F=x is applied can be found by integrating the force over the distance. The work done W is given by:
W = ∫x=0 to x=1 F(x) dx
W = ∫x=0 to x=1 x dx
W =[x2/2] from 0 to 1
W = (12/2) - (02/2)
W = 1/2 units of work
The work done in moving a particle from x=0 to x=1 when a variable force F=x is applied can be found by integrating the force over the distance. The work done W is given by:
W = ∫x=0 to x=1 F(x) dx
W = ∫x=0 to x=1 x dx
W =[x2/2] from 0 to 1
W = (12/2) - (02/2)
W = 1/2 units of work
The work done in moving a particle from x=0 to x=1 when a variable force F=x is applied can be found by integrating the force over the distance. The work done W is given by:
W = ∫x=0 to x=1 F(x) dx
W = ∫x=0 to x=1 x dx
W =[x2/2] from 0 to 1
W = (12/2) - (02/2)
W = 1/2 units of work
Tagged under Physics · Work, Power & Energy · 2021