Physics · Electronics
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Consider a peak rectifier fed by a 60-Hz sinusoid having a peak value Vp = 100 V. Let the load resistance R = 10 kn. Calculate the fraction of the cycle during which the diode is conducting.
- A
1.06 %
- B
2.06%
- C
3.18%
- D
4.28%
Option C is correct since the best explanation is :
w Δt ~ √(2Vr/Vp)
= √(2 X 2/100)
= 0.2 rad or 3.18% of the cycle
As per the calculation, this option is incorrect.Option C is correct since the best explanation is :
w Δt ~ √(2Vr/Vp)
= √(2 X 2/100)
= 0.2 rad or 3.18% of the cycle
As per the calculation, this option is incorrect.Option C is correct since the best explanation is :
w Δt ~ √(2Vr/Vp)
= √(2 X 2/100)
= 0.2 rad or 3.18% of the cycle
Option C is correct since the best explanation is :
w Δt ~ √(2Vr/Vp)
= √(2 X 2/100)
= 0.2 rad or 3.18% of the cycle
As per the calculation, this option is incorrect.Option C is correct since the best explanation is :
w Δt ~ √(2Vr/Vp)
= √(2 X 2/100)
= 0.2 rad or 3.18% of the cycle
Tagged under Physics · Electronics · 2021