Physics · Wave Motion and Sound
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The distance between two consecutive crests of a travelling wave is 10 cm. If the speed of the wave is 50 cm/s, then its frequency would be:
- A
40 Hz
- B
1/5 Hz
- C
5 Hz
- D
500 Hz
The equation is given by:
v = f \λ
On rearranging the equation for frequency, we get,
f = v/λ
Putting values:
f = (50 cm/s)/10 cm
f = 5 Hz
As per calculation, this option is incorrect.
As per calculation, this option is incorrect.
The equation is given by:
v=f\\\
On rearranging the equation for frequency, we get,.
f = v/X
Putting values:
f = (50 cm/s)/10 cm f = 5 Hz
As per calculation, this option is incorrect.
Tagged under Physics · Wave Motion and Sound · 2021