Physics · Work, Power & Energy
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A force of F = 20 + 10y N is acting in y direction, work done by this force to move the particle from y= 0 to y = 1m?
- A
20 J
- B
15 J
- C
5 J
- D
25 J
The work done by the force F can be calculated using the formula W = ∫F.dy, where ∫F.dy represents the integral of the force F with respect to the displacement dy. In this case, the integral can be written as:
W = ∫(20+10y)dy from y=0 to y=1
Evaluating this integral gives:
W = [20y + 5y2] from y=0 to y=1
Substituting the limits of integration gives:
W = [20(1) + 5(1)2] - [20(0) + 5(0)2]
Simplifying this expression gives:
W = 25 J
Therefore, the work done by the force F to move the particle from y=0 to y=1 m is 25 J.
Refer to the explanation below.
Refer to the explanation below.
Refer to the explanation below.
The work done by the force F can be calculated using the formula W = ∫F.dy, where ∫F.dy represents the integral of the force F with respect to the displacement dy. In this case, the integral can be written as:
W = ∫(20+10y)dy from y=0 to y=1
Evaluating this integral gives:
W = [20y + 5y2] from y=0 to y=1
Substituting the limits of integration gives:
W = [20(1) + 5(1)2] - [20(0) + 5(0)2]
Simplifying this expression gives:
W = 25 J
Therefore, the work done by the force F to move the particle from y=0 to y=1 m is 25 J.
Tagged under Physics · Work, Power & Energy · 2021