Physics · Forces and Motion

You will find the distance traveled in 5 and 4 seconds individually. After subtracting these two terms and equating it to 36 meters, all variables are fulfilled other than a which we can solve for.In the below equations, s is distance, a is acceleration, and t is time.In 4 seconds, the truck covers:s = 1/2 at2s = 1/2 (a) 42s = 1/2 (a) (16)s = 8 (a) metersIn 5 seconds, the truck coverss = 1/2 a t2s = 1/2 (a) 52s = 1/2 (a) 25s = 12.5 (a) metersThe distance covered in 5 seconds minus the distance covered in 4 seconds is the distance (36 meters) covered in the 5th second.36 = 12.5 a - 8 a36 meters = 4.5 seconds2 (a)a = acceleration = 8 m/s2

This value is incorrect. It results from incorrect calculations or assumptions about the time and distance relationship under constant acceleration.

This is the correct answer. By calculating the distance covered in the 5th second using the formula for uniform acceleration, we deduce that acceleration is 8 m/s2.

This value is too high, which means the calculated acceleration is overestimated. Check the calculations for any arithmetic mistakes.

This value is double the correct answer, indicating a misunderstanding of the motion equations or a calculation error.

This is an overestimate. The calculations need to be revisited to ensure the correct use of formulas.

This value is too low, suggesting an error in applying the kinematic equations or misinterpretation of the data.