Chemistry · D and f Block Elements
Work through this past-paper style MCQ, then read the full explanation. Practice more chemistry questions on mMCQ with adaptive practice and topic analytics.
Which of the following has the maximum number of unpaired d electrons?
- A
Mg2+
- B
Ti3+
- C
V3+
- D
Fe2+
The correct answer is Fe2+. The electron configuration for Fe2+ is [Ar] 3d6, with the 3d subshell holding six electrons: four of these are unpaired due to Hund's rule, which states that electrons fill degenerate orbitals singly first. Mg2+ lacks d electrons entirely, Ti3+ has only one unpaired d electron ([Ar] 3d1), and V3+ has two unpaired d electrons ([Ar] 3d2).
Mg2+ has the electron configuration 1s2 2s2 2p6. It lacks d electrons entirely, resulting in no unpaired d electrons.
Ti3+ has the electron configuration [Ar] 3d1, meaning it contains only one unpaired d electron.
V3+ has the electron configuration [Ar] 3d2. It has two unpaired d electrons, following Hund's rule of maximum multiplicity.
Fe2+ has the electron configuration [Ar] 3d6. According to Hund's rule, it has four unpaired d electrons, making it the option with the most unpaired d electrons among the given choices.
Tagged under Chemistry · D and f Block Elements · 2016