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MDCAT
Chemistry
2011

Chemistry · Stoichiometry

Work through this past-paper style MCQ, then read the full explanation. Practice more chemistry questions on mMCQ with adaptive practice and topic analytics.

Question

By heating 25g of limestone (CaCO3) , the weight of carbon dioxide produced is:

Options
  • A

    14 g

  • B

    71 g

  • C

    11 g

  • D

    2 g

  • E

    10 g

Explanation

Limestone is primarily composed of calcium carbonate (CaCO3). When heated, it decomposes according to the reaction:

CaCO3 --> CaO + CO2

From the stoichiometric relationship, 100g of CaCO3 decomposes to produce 44g of CO2. Therefore, for 25g of CaCO3, the amount of CO2 produced is calculated as follows:

(25g CaCO3 / 100g CaCO3) * 44g CO2 = 11g CO2

Thus, the correct answer is 11g. Other options either overestimate or underestimate this calculated mass based on incorrect stoichiometric assumptions.

This option incorrectly assumes a different stoichiometric proportion.

This value is much higher than the possible mass of CO2 produced, considering the initial mass of limestone.

Based on stoichiometry: 100g CaCO3 produces 44g CO2, hence 25g CaCO3 produces 11g CO2. This is the correct answer.

This value underestimates the mass of CO2 produced from 25g of CaCO3.

This value is close but slightly underestimates the correct stoichiometric calculation.

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Tagged under Chemistry · Stoichiometry · 2011