Chemistry · Stoichiometry
Work through this past-paper style MCQ, then read the full explanation. Practice more chemistry questions on mMCQ with adaptive drills and topic analytics.
C12H22O11 + conc. H2SO4 → 12 C + ? + H2SO4
- A
11 H2O
- B
11 O2
- C
11 CO2
- D
11 H2
Comparing reactant and product side we can see that there is a difference of 22 H and 11 O. That means the compound that we can make of it is 11 H2O. Hence the answer is A.
This is correct. The difference of 22 H and 11 O atoms on the reactant side corresponds to 11 molecules of water (H2O) on the product side.
This is incorrect. Oxygen in the form of O2 would imply a different reaction and doesn't account for the hydrogen atoms present in the sugar molecule.
This is incorrect. Carbon from the sugar is converted to elemental carbon (C), not carbon dioxide (CO2), in this reaction.
This is incorrect. The hydrogen is balanced in the form of water (H2O) and not as molecular hydrogen (H2).
Tagged under Chemistry · Stoichiometry · 2016