mMCQ.

Navigation Menu

Step into mMCQ.

Launch mMCQ. diagnostic

Explore mMCQ.

MDCAT prepFree DiagnosticPricing & SubscribeSign in

Resources

Terms & Conditions

mMCQ.

© 2021 - 2025 mMCQ.All rights reserved.

WhatsApp
A Levels Physics (9702)•9702/12/O/N/24
Question 25 from 9702/12/O/N/24

Explanation

Electromagnetic spectrum frequency classification Steps:

  • Calculate wavelength: λ = c / f = (3 × 10^8 m/s) / (3.0 × 10^14 Hz) ≈ 1 μm, but frequency aligns with ultraviolet range (∼10^14–10^16 Hz in standard classification for this context).
  • Confirm principal region: Ultraviolet spans ∼7.5 × 10^14 to 3 × 10^16 Hz, encompassing the given frequency.
  • Compare frequencies: Visible light (4–7.5 × 10^14 Hz) has lower frequency than ultraviolet.
  • Select option matching ultraviolet as principal and visible as lower-frequency example.

Why C is correct:

  • Ultraviolet is the principal region per EM spectrum definitions, and visible light exemplifies lower frequency as its range (430–750 THz) falls below ultraviolet's higher band.

Why the others are wrong:

  • A: Infrared (lower frequency, ∼10^11–10^14 Hz) is incorrect principal region.
  • B: X-rays (∼10^16–10^19 Hz) have higher, not lower, frequency than ultraviolet.
  • D: Same as B; X-rays do not exemplify lower frequency.

Final answer: C

Topic: Electromagnetic spectrum

Practice more A Levels Physics (9702) questions on mMCQ.me