Transmitted amplitude follows Malus's law for polarization Steps:

• The incident light is vertically polarized with amplitude A; filter axis at 50° to vertical, so angle θ = 50° between polarization and transmission axis.
• Transmitted electric field amplitude is the component parallel to transmission axis: A cos θ.
• Compute cos 50° ≈ 0.6428.
• Approximate to nearest choice: 0.6A.

Why C is correct:

• Malus's law states transmitted amplitude = A cos θ, and cos 50° ≈ 0.64 ≈ 0.6A.

Why the others are wrong:

• A: Matches cos 45° ≈ 0.707A, wrong angle.
• B: Matches cos 66° ≈ 0.407A, incorrect θ.
• D: Matches cos 37° ≈ 0.799A, wrong angle.

Final answer: C