Maximum pressure occurs when resting on the smallest face Steps: - Calculate volume V = 12.0 cm × 15.0 cm × 10.0 cm = 1800 cm³ = 0.0018 m³. - Determine mass m = ρ V, with ρ = 11.3 kg/m³ (adjusted for lead density in SI units), m = 11.3 × 0.0018 ≈ 0.0203 kg. - Calculate weight F = m g ≈ 0.0203 × 9.8 ≈ 0.199 N. - Smallest face area A = 10.0 cm × 12.0 cm = 120 cm² = 0.012 m²; P = F / A ≈ 0.199 / 0.012 ≈ 16 Pa. Why D is correct: - Pressure P = weight / contact area; by definition, maximum P when A is minimized (smallest face), yielding 16 Pa via P = ρ g h_max with h_max = 0.15 m. Why the others are wrong: - A: Matches density value alone, ignores weight and area. - B: Uses incorrect ρ ≈ 1.13 kg/m³ or smallest h = 0.10 m. - C: Uses intermediate h = 0.12 m or approximate ρ g h ≈ 11 Pa. …