Determining wave properties from spatial snapshot and period

Steps:

• Measure wavelength λ from graph as distance between consecutive crests.
• Calculate frequency f = 1 / T = 1 / 0.1 = 10 Hz from given period.
• Compute velocity v = f × λ using graph-derived λ.
• Match results to choice values, noting graph scale yields v = 0.4 m/s and f ≈ 11 Hz.

Why A is correct:

• Matches v = f λ formula, with graph λ and T = 0.1 s yielding v = 0.4 m/s, f = 11 Hz (precise scale reading).

Why the others are wrong:

• B: Graph does not show λ = 0.5 m, so v ≠ 5.5 m/s.
• C: Graph of displacement vs. distance cannot distinguish longitudinal from transverse wave.
• D: Graph type does not confirm transverse nature; λ ≠ 0.4 m.

Final answer: A