Torque equilibrium about the hinge

Steps:

• Weight acts at center of mass, 2.0 m from hinge; clockwise torque = 200 N × 2.0 m = 400 Nm.
• Cable attaches at 3.5 m from hinge (4.0 m - 0.5 m).
• Counterclockwise torque from cable = T sin(35°) × 3.5 m, where sin(35°) ≈ 0.574.
• For equilibrium, T × 0.574 × 3.5 = 400; T = 400 / (0.574 × 3.5) ≈ 200 N.

Why C is correct:

• 200 N satisfies the torque balance formula, τ = F × d × sinθ, equating moments for static equilibrium.

Why the others are wrong:

• A: Underestimates by using shorter lever arm or neglecting angle.
• B: Minor miscalculation, perhaps approximating sin(35°) as 0.6.
• D: Overestimates by using full bar length or cos(35°) instead of sin(35°).

Final answer: C