Stationary waves in closed pipes have discrete frequencies Steps:

• In a pipe closed at one end, standing waves form with a node at the closed end and antinode at the open end.
• Possible lengths satisfy L = (2n-1) λ / 4 for integer n ≥ 1, so frequencies are f_n = (2n-1) v / (4L).
• The question does not specify the harmonic (n), so multiple frequencies are possible: ~142 Hz (n=1), 425 Hz (n=2), ~708 Hz (n=3), etc.
• Without knowing n, the frequency cannot be uniquely determined.

Not enough information.

Why A is correct:

• 425 Hz matches the first overtone (n=2, f=3v/4L=3×340/(4×0.60)=425 Hz), but the question does not indicate this mode.

Why the others are wrong:

• B: 850 Hz is an even multiple (not possible in closed pipes).
• C: 1130 Hz does not match any odd harmonic.
• D: 2270 Hz does not match any odd harmonic.

Final answer: Not enough information.