Torque equilibrium about the pivot Steps:

• Identify torques acting on the rod: the rod's weight W acts downward at its center of mass (100 cm from pivot if at end), producing clockwise torque W × 1 m.
• The 60 N hanging weight creates tension T = 60 N in the string (frictionless pulley, equilibrium).
• The tension provides counterclockwise torque T × d, where d is the horizontal distance from pivot to attachment point (or effective moment arm).
• Set net torque to zero: 60d = W × 1, so W = 60d.

Not enough information: Attachment point and pulley position unspecified, so d unknown; cannot determine exact W.

Why C is correct:

• Not applicable; problem lacks details for unique solution matching 80 N.

Why the others are wrong:

• A: Would require d = 0.5 m, possible but unconfirmed.
• B: Would require d = 1 m, possible but unconfirmed.
• D: Would require d ≈ 2.33 m > rod length, impossible.

Final answer: Not enough information.