mMCQ.

Navigation Menu

Step into mMCQ.

Launch mMCQ. diagnostic

Explore mMCQ.

MDCAT prepFree DiagnosticPricing & SubscribeSign in

Resources

Terms & Conditions

mMCQ.

© 2021 - 2025 mMCQ.All rights reserved.

WhatsApp
A Levels Physics (9702)•9702/11/O/N/21
Question 6 from 9702/11/O/N/21

Explanation

Projectile Motion Displacement Components

Steps:

  • In projectile motion with negligible air resistance, horizontal velocity is constant, so horizontal displacement increases linearly with time.
  • Vertical velocity changes due to constant gravitational acceleration, so vertical displacement follows a parabolic curve with time.
  • Graph q shows linear increase, matching horizontal displacement.
  • Graph p shows parabolic variation, matching vertical displacement.

Why B is correct:

  • Horizontal displacement is sx=vxts_x = v_x tsx​=vx​t (linear), and vertical is sy=vy0t−12gt2s_y = v_{y0} t - \frac{1}{2} g t^2sy​=vy0​t−21​gt2 (parabolic), aligning q with horizontal and p with vertical.

Why the others are wrong:

  • A: Assigns q (linear) to vertical, but vertical displacement is parabolic, not linear.
  • C: Assigns r to horizontal, but r does not show linear increase.
  • D: Assigns r to horizontal and q to vertical, mismatching both linear and parabolic behaviors.

Final answer: B

Topic: Equations of motion

Practice more A Levels Physics (9702) questions on mMCQ.me