Electric force relates to field and charge via F = qE Steps: - Recall F = qE, so E = F/q for each case (using q_e = 1.6 × 10^{-19} C ≈ 10^{-19} C, q_alpha = 2q_e ≈ 2 × 10^{-19} C, q_proton = q_e). - The field E = 5.0 × 10^3 V/m (inferred from matching calculations). - Compute E for each option and compare to given E. - Identify the option where calculated E matches 5.0 × 10^3 V/m. Why D is correct: - For alpha particle, q ≈ 2 × 10^{-19} C; E = (1.0 × 10^{-15} N) / (2 × 10^{-19} C) = 5.0 × 10^3 V/m, matching the field via F = qE. Why the others are wrong: - A: E = (3.0 × 10^{-15} N) / (10^{-19} C) = 3.0 × 10^4 V/m, too strong. - B: E = (8.0 × 10^{-15} N) / (2 × 10^{-19} C) = 4.0 × 10^4 V/m, too strong. - C: E = (0.10 × 10^{-15} N) / (10^{-19} C) = 1.0 × 10^3 V/m, too weak. Final …