A Levels Physics (9702)•9702/12/O/N/20

Explanation
Difference in extension determines spring constant via Hooke's law Steps:
- Convert units: masses to 0.06 kg and 0.10 kg, distances to 0.14 m and 0.12 m, g = 9.8 m/s².
- Change in extension Δx = initial distance - final distance = 0.14 m - 0.12 m = 0.02 m (since more mass increases extension, decreasing distance to floor).
- Change in force ΔF = (0.10 kg - 0.06 kg) × 9.8 m/s² = 0.04 kg × 9.8 m/s² = 0.392 N.
- Spring constant k = ΔF / Δx = 0.392 N / 0.02 m = 19.6 N/m.
Not enough information (calculated k = 19.6 N/m does not match any option).
Why C is correct:
- Not applicable; calculation yields 19.6 N/m, inconsistent with options.
Why the others are wrong:
- A: Too small; ignores proper force-extension ratio.
- B: Too small; ignores proper force-extension ratio.
- D: Too small; ignores proper force-extension ratio.
Final answer: Not enough information.
Topic: Elastic and plastic behaviour
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