Voltmeter parallels R1, dividing current equally

Steps:

• R1 and voltmeter (both 100 kΩ) in parallel: equivalent resistance = (100 × 100) / (100 + 100) = 50 kΩ.
• Total circuit resistance: 50 kΩ + R2 (100 kΩ) = 150 kΩ.
• Total current from battery: 6.0 V / 150 kΩ = 40 μA.
• Current splits equally in parallel branches: 40 μA / 2 = 20 μA through R1.

Why A is correct:

• Kirchhoff's current law: equal resistances in parallel divide total current equally.

Why the others are wrong:

• B: Assumes voltmeter has infinite resistance, yielding total current of 6 V / 200 kΩ = 30 μA through series R1 and R2.
• C: Equals total current through parallel combination, not just R1 branch.
• D: Assumes only R1 connected, ignoring R2 and voltmeter (6 V / 100 kΩ = 60 μA).

Final answer: A