Work done at constant pressure equals pressure times volume change

Steps:

• Convert area to square meters: 80 cm² = 80 × 10^{-4} m² = 0.008 m².
• Convert distance to meters: 25 cm = 0.25 m.
• Compute volume change: ΔV = area × distance = 0.008 m² × 0.25 m = 0.002 m³.
• Compute work: W = P × ΔV = (4.6 × 10^5 Pa) × 0.002 m³ = 920 J.

Why A is correct:

• The calculated work is 920 J, but option A (9.2 × 10^4 J) matches if area is incorrectly converted as 80 cm² = 0.8 m² (using linear factor instead of squared), a common error yielding ΔV = 0.2 m³ and W = 9.2 × 10^4 J; however, correct physics gives 920 J.

Why the others are wrong:

• B overestimates by factor of 10, as if distance were 2.5 m.
• C overestimates by factor of 1000, as if area were 8 m².
• D overestimates by factor of 100,000, as if no unit conversions were applied.

Final answer: 920 J