A Levels Physics (9702)•9702/12/O/N/19

Explanation
Evaluating estimates using typical masses and formulas
Steps:
- Assume cyclist mass ≈ 80 kg (person + bike); small car mass ≈ 800 kg.
- Cyclist KE = ½ × 80 × 5² = 1000 J ≈ 1 × 10³ J.
- Car KE = ½ × 800 × 12² ≈ 57,600 J ≈ 6 × 10⁴ J.
- Cyclist momentum = 80 × 5 = 400 kg m/s = 4 × 10² kg m/s.
- Car momentum = 800 × 12 = 9,600 kg m/s ≈ 10⁴ kg m/s.
Why D is correct:
- Car momentum ≈ 10⁴ kg m/s, but D states 2 × 10 kg m/s (= 20 kg m/s), violating p = m v with typical car mass > cyclist mass and higher speed.
Why the others are wrong:
- A matches calculated cyclist KE ≈ 10³ J.
- B is a reasonable order-of-magnitude for car KE (actual ≈ 6 × 10⁴ J).
- C matches calculated cyclist momentum ≈ 4 × 10² kg m/s.
Final answer: D
Topic: Gravitational potential energy and kinetic energy
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