Torque balance for rotational equilibrium Steps:

• Identify torques about pivot P: rod's weight W acts downward at the center of mass (midpoint, 100 cm from either end).
• Tension T = 60 N (since frictionless pulley and hanging weight in equilibrium) acts upward at the string's attachment point on the rod.
• For horizontal equilibrium, clockwise torque = counterclockwise torque: W × (distance from P to center) = 60 × (distance from P to attachment).
• Positions of P and attachment point relative to the 200 cm rod are unspecified, so W cannot be calculated numerically.

Why C is correct:

• Not applicable; lacks specificity to confirm 80 N.

Why the others are wrong:

• A: Insufficient details to verify or rule out 30 N.
• B: Insufficient details to verify or rule out 60 N.
• D: Insufficient details to verify or rule out 140 N.

Not enough information. Final answer: Not enough information.