A Levels Physics (9702)•9702/14/M/J/25

Explanation
Potentiometer null method for measuring unknown emf
Steps:
- Connect known emf battery across uniform wire XY to create potential gradient.
- Link unknown cell in opposition to battery, with galvanometer from cell terminal to jockey on wire.
- Adjust jockey for null galvanometer deflection, ensuring no current flows through unknown cell.
- Calculate unknown emf as E = (l/L) × known emf, where l is balancing length and L is wire length.
Why B is correct:
- It opposes unknown emf to potential drop along wire, allowing null balance per potentiometer principle where E_unknown = I × ρ × l (ρ is resistance per unit length, I is current).
Why the others are wrong:
- A: Galvanometer directly across wire, measures resistance not emf.
- C: Unknown cell powers wire, reverses setup and draws current from it.
- D: Series connection of cells bypasses null method, no balancing point.
Final answer: B
Topic: Potential dividers
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