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A Levels Physics (9702)•9702/13/M/J/25
Question 17 from 9702/13/M/J/25

Explanation

Efficiency in Electric Motors Steps:

  • Efficiency is the ratio of useful output power to input power, expressed as a percentage.
  • Formula: Output power = (efficiency × input power) / 100.
  • Input power = 1 kW, efficiency = 53%.
  • Output power = (53 × 1) / 100 = 0.53 kW.

Why A is correct:

  • Directly applies the efficiency formula: output = input × (efficiency/100).

Why the others are wrong:

  • B: Assumes 90% efficiency, not 53%.
  • C: Approximates input divided by efficiency (1/0.53 ≈ 1.89 kW), which is total power needed for 1 kW output.
  • D: Unrelated; far exceeds input power, violating energy conservation.

Final answer: A

Topic: Potential difference and power

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