Moment balance about end P Steps:

• Bar length L = 0.5 m; center 0.25 m from P.
• Upward force 360 N at Q gives moment about P: 360 × 0.5 = 180 Nm (counterclockwise).
• Block moment about P: 400 × 0.25 = 100 Nm (clockwise).
• Bar weight moment about P: 200 × d = clockwise moment, d = distance from P to bar's CG.
• For force just sufficient to lift P (reaction at Q = 0): 180 = 100 + 200d → 200d = 80 → d = 0.4 m.

Why D is correct:

• Equilibrium requires moments about P to balance with zero reaction at Q, giving d = 0.4 m by torque equation.

Why the others are wrong:

• A: 0.5 m would make bar CG at Q, unbalancing moments (180 ≠ 100 + 200×0.5 = 200).
• B: 0.1 m gives moments 180 ≠ 100 + 200×0.1 = 120.
• C: 0.25 m gives moments 180 ≠ 100 + 200×0.25 = 150.

Final answer: D