A Levels Physics (9702)•9702/13/M/J/25

Explanation
Conservation of Linear Momentum in Collisions
Steps:
- Identify initial momentum: only the moving nucleus has momentum along its path; stationary nucleus contributes zero.
- Apply conservation: total momentum vector before equals total after, with no external forces in vacuum.
- Analyze paths: post-collision velocities must sum to initial momentum vector, including zero perpendicular component.
- Check diagrams: impossible if net perpendicular momentum appears post-collision.
Why C is correct:
- In C, both nuclei deflect to the same side, creating net perpendicular momentum, violating conservation of linear momentum (total momentum must remain along initial direction).
Why the others are wrong:
- A: Incident nucleus glances off; target moves forward—momentum vectors balance along initial direction.
- B: Head-on collision; both move forward with reduced speeds—conserves momentum magnitude and direction.
- D: Incident rebounds slightly, target deflects oppositely—perpendicular components cancel, conserving total momentum.
Final answer: C
Topic: Linear momentum and its conservation
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