Approximate volume uncertainty via equatorial belt method Steps:

• Compute radius r = diameter / 2 = 5.2 / 2 = 2.6 cm and δr = 0.1 / 2 = 0.05 cm.
• Compute equatorial circumference C = 2πr ≈ 2 × 3.14 × 2.6 = 16.3 cm.
• Approximate absolute uncertainty δV ≈ C × δr = 16.3 × 0.05 = 0.815 cm³.
• Round to 0.8 cm³ based on significant figures in measurement.

Why B is correct:

• This uses the definition of volume change as surface differential ≈ equatorial strip area (circumference × δr), a simplified propagation for sphere volume uncertainty.

Why the others are wrong:

• A. 0.2 cm³ underestimates by factor of 4, ignoring circumference scaling.
• C. 1 cm³ approximates δ(r³) = 3r² δr but neglects π and 4/3 factors in sphere volume.
• D. 7 cm³ overestimates by using full δd = 0.1 cm as δr instead of halving for radius.

Final answer: B