Power dissipation depends on current through each resistor

Steps:

• Identify circuit configuration: assume series-parallel setup with resistors labeled A (across battery), B/C in parallel branches, D in series.
• Calculate equivalent resistance: parallel branches reduce total R, increasing overall current.
• Determine current in each: A carries full battery current; B and C share it equally; D has reduced current post-parallel.
• Compare powers: P = I²R; highest I yields highest P for identical R.

Why A is correct:

• Resistor A has the maximum current (full circuit current), so by P = I²R, it dissipates the most power.

Why the others are wrong:

• B: Lower current than A due to parallel sharing.
• C: Same as B, split current reduces power.
• D: Positioned after parallel section, lowest current.

Not enough information: Diagram not provided, limiting precise analysis.

Final answer: A