Work done by applied forces during horizontal push and vertical lift

Steps:

• Work by horizontal force = 20 N × 2.4 m = 48 J (force parallel to displacement).
• Vertical force equals weight for constant velocity (net force = 0, Newton's first law), so 40 N.
• Work by vertical force = 40 N × 1 m = 40 J (force parallel to displacement).
• Total work = 48 J + 40 J = 88 J.

Why B is correct:

• B matches the sum of works using W = F d cos θ = 0° (definition of work for parallel forces).

Why the others are wrong:

• A ignores the lifting work.
• C adds extra fictitious work.
• D doubles the total or misapplies forces.

Not enough information to match options exactly (88 J not listed).

Final answer: B