A Levels Physics (9702)•9702/13/M/J/23

Explanation
Work done equals force times extension for constant applied force
Steps:
- The applied force stretches the spring from unstretched length L0 to L1.
- The extension, or displacement of the end, is ΔL = L1 - L0.
- Work done by the constant force F over this displacement is W = F × ΔL.
- Substitute values to get W = F(L1 - L0).
Why B is correct:
- It follows the work formula W = F × displacement, where displacement is the extension L1 - L0 under constant force F.
Why the others are wrong:
- A: Assumes average force F/2 for variable loading like Hooke's law, but applied force is constant F.
- C: Multiplies by unstretched length L0, ignoring the actual displacement ΔL.
- D: Uses undefined L instead of specified L1 for the stretched length.
Final answer: B
Topic: Elastic and plastic behaviour
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