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A Levels Physics (9702)•9702/11/M/J/23
Question 39 from 9702/11/M/J/23

Explanation

Net change in mass number during radioactive decay

Steps:

  • Calculate original mass number: A = protons + neutrons = 92 + 143 = 235.
  • Each α-particle removes 4 nucleons (2 protons + 2 neutrons), so 3 α-particles reduce A by 3 × 4 = 12.
  • Each β⁻-particle converts a neutron to a proton but does not change total nucleons, so 4 β-particles reduce A by 0.
  • Final mass number of nucleus X: A = 235 - 12 + 0 = 223.

Why D is correct:

  • Not applicable; calculation yields ^{223}X, but options lack this—possibly a problem error.

Why the others are wrong:

  • A: ^{231}X assumes only 1 α-particle (ΔA = -4), ignoring the other 2 α-decays.
  • B: ^{218}X assumes excessive decay (ΔA = -17), not matching 3 α + 4 β.
  • C: ^{222}X assumes 4 α-particles (ΔA = -16) or U-234 start, contradicting given neutrons.

Final answer: Not enough information.

Topic: Radioactive decay

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