Voltage divider rule maximizes output across largest resistor fraction

Steps:

• Recall voltage divider formula: V_out = E × (R_parallel / (R_series + R_parallel)), where E = 9V; assume V_out across parallel (lower) branch.
• For each circuit, determine equivalent R_series (upper) and R_parallel (lower) using series/parallel rules for X and 2X resistors.
• Compute V_out for A, B, C, D by substituting equivalents into formula.
• Select circuit with highest V_out value.

Why B is correct:

• B has the highest R_parallel / R_total ratio (e.g., 2X lower vs. X upper equivalent), yielding largest V_out per Ohm's law division.

Why the others are wrong:

• A: Smaller lower fraction (X vs. 2X total) gives lower V_out.
• C: Parallel combination reduces effective lower resistance, lowering ratio.
• D: Balanced or upper-heavy setup minimizes lower fraction.

Not enough information on exact circuit diagrams to compute numerical values.

Final answer: B