Ball bobs in SHM; total path length is 4 × amplitude × number of cycles Steps:

• Interpret distance between trough and adjacent peak as wavelength λ = 2.4 m.
• Use deep-water gravity wave dispersion: f = √(g / (2π λ)), with g = 9.8 m/s², so f = √(9.8 / (2π × 2.4)) ≈ 0.81 Hz.
• Number of cycles in 5 s = f × 5 ≈ 4.
• Total distance = 4 × 0.70 m × 4 = 11.2 m. Why C is correct:
• Matches 4A per cycle in vertical SHM, with cycles from dispersion relation f ≈ 0.81 Hz × 5 s = 4. Why the others are wrong:
• A: Assumes 2 cycles (e.g., using given f = 0.20 Hz doubled), giving 5.6 m.
• B: Wave travel distance doubled (v t = 4.8 m × 2, misusing λ = 4.8 m).
• D: Approximate circular path length (2π A × 4 cycles ≈ 17.6 m, adjusted up). Final answer: C